The a3-b3formula is called the distinction of cubes (of 2 numbers) formula. The a cube minus b cube formula isused to find the difference between the two cubes without in reality calculating the cubes. Also, that is used to factorize the binomials the cubes.In this section, we will be stating the various aspects of the a3-b3formula, in addition to solved examples, and understand the identityinvolved.

You are watching: A^3-b^3 formula

What Is a^3-b^3 Formula?

Thea3-b3formula have the right to beverified, bymultiplying(a - b) (a2+ab + b2) and see whether you acquire a3- b3.The a3- b3formula or the difference ofcubesformula is defined below:

a3-b3Formula = a3- b3= (a -b) (a2+ ab + b2)

You deserve to remember these indicators using the following trick.

*

Let us discover thea3-b3formula v a couple of solved examples.

Proof that a3-b3 Formula

Let us verify the a cube minus b cube formula. To provethata3- b3= (a -b) (a2+ ab + b2) we have to prove right here LHS = RHS. Lets start with the complying with steps.LHS =a3- b3On resolving RHS side we get,= (a -b) (a2+ abdominal + b2)On multiply the a and also b separatelywith(a2+ ab + b2) we get= a (a2+ abdominal muscle + b2) - b(a2+ ab + b2)= a3 + a2b + ab2 - a2b - ab2- b3= a3 + a2b - a2b + ab2- ab2- b3=a3- 0 - 0 - b3=a3- b3Hence proved, LHS = RHS



Want come find complicated math services within seconds?
Use our totally free online calculator to solve an overwhelming questions. Through chrischona2015.org, discover solutions in straightforward and easy steps.

Book a complimentary Trial Class


Examples on a^3-b^3Formula

Example 1:Find the worth of 1083-83using the a^3-b^3formula.

Solution:

To find:1083-83.

Let us assume that a = 108and b = 8.

We will substitute these in the formula ofa3- b3.

a3- b3= (a -b) (a2+ abdominal muscle + b2)

1083-83= (108-8)(1082+(108)(8) + 82)

= (100) (11664+864+64)

= (100)(12592)

=1259200

Answer:1083-83=1,259,200.

Example 2:Factorize the expression 27x3-125usinga^3-b^3 formula.

Solution:

To factorize: 27x3- 125.

We will usage thea3- b3formula come factorize this.

We can write the offered expression as

27x3- 125 = (3x)3- 53

We will substitute a = 3x and also b = 5in the formula ofa3- b3.

a3- b3= (a -b) (a2+ ab + b2)

(3x)3-53=(3x-5)((3x)2+(3x)(5)+52)

= (3x-5) (9x2+15x+25)

Answer:27x3-125= (3x -5) (9x2+ 15x + 25).

Example 3: Simplify 193 - 203 utilizing a cube minusb cubeformula.

Solution: To find193 - 203

Let united state assume a = 19 and also b = 20Using formulaa3- b3= (a - b) (a2+ abdominal muscle + b2)We will certainly substitute these in thea3- b3formulaa3- b3= (a -b) (a2+ abdominal muscle + b2)193-203= (19-20)(192+(19)(20)+202)= (-1)(361+380+400)= (-1)(1141)= -1141Answer:193-203= -1141.


FAQ's top top a^3-b^3Formula

What Is the expansion of a3-b3 Formula?

a3-b3formula is check out as a cube minus b cube. Its expansion is to express asa3-b3=(a -b) (a2+ abdominal muscle + b2).

What Is thea3-b3 Formula in Algebra?

The a3-b3formula is also known as one of the necessary algebraic identiy. That is read as a cube minus b cube. That a3-b3formula is to express asa3-b3=(a -b) (a2+ ab + b2).

How To simplify Numbers Usingthea3-b3 Formula?

Let us recognize the usage of the a3-b3formula through the help of the complying with example.Example: discover the worth of 103- 23using the a3-b3formula.To find:103-23Let us assume that a = 10and b = 2.We will certainly substitute these in the formula ofa3- b3.a3- b3= (a -b) (a2+ abdominal muscle + b2)103-23= (10-2)(102+(10)(2)+22)= (8) (100+20+4)= (8)(124)=992Answer:103-23= 992.

How To usage thea3-b3 Formula offer Steps?

The adhering to steps are complied with while usinga3-b3formula.

See more: How Many Days Are In 15 Years, Days In A Year, How Many Days Old Are You At 15 Years

Firstlyobserve the pattern of the numbers whether thenumbers have ^3 as power or not.Write under the formula ofa3- b3 a3- b3= (a -b) (a2+ abdominal + b2)substitute the worths ofa and also b in thea3-b3formula and also simplify.