tesla and a force of 1.40 times 10 come the minus 16 newtons is being applied on this moving charge and from every this information, we need to figure out what is the angle in between the velocity and the magnetic field? We additionally know the charge... I didn't compose it down yet the charge is the elementary fee on an electron— 1.60 time 10 come the minus 19 coulombs. So pressure is the charge times the rate times the magnetic field strength times sin of the angle between them and we have the right to solve this for sin Θ by splitting both political parties by qvB. For this reason sin Θ is force split by fee times rate times magnetic ar strength and also then us take the station sin of both sides to number out the angle Θ. So Θ is the inverse sin the F over qvB and also so we plugin numbers: station sin the 1.40 times 10 come the minus 16 newtons divided by the fee times the speed times the magnetic ar strength and we gain 10.1 degrees but that's no the end of the story due to the fact that this is the photo for i beg your pardon this is the solution; we have actually the velocity rather to the right when the magnetic ar is to the right and also this would certainly be one angle in between them of 10.1 degrees but the same magnitude pressure would take place if the velocity were nearly anti-parallel to the magnetic ar such that this, you know, referral angle which is what her calculator speak you the the smallest angle that gives the systems this reference angle is 10.1 or 10.0787 degrees however the edge Θ is gonna begin from this magnetic field and also go all the method to the velocity vector. So this is a 180 degrees minus this 10.0787 degrees and also this functions out come 170 degrees.">

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This is college Physics Answers with Shaun Dychko. One electron is relocating at 4.00 times 10 come the 3 meter per 2nd in a magnetic field with toughness 1.25 tesla and also a force of 1.40 times 10 to the minus 16 newtons is being used on this moving charge and also from all this information, we need to figure out what is the angle in between the velocity and also the magnetic field? We additionally know the charge... I didn"t compose it down however the fee is the elementary fee on one electron— 1.60 times 10 come the minus 19 coulombs. So pressure is the charge times the rate times the magnetic field strength times sin of the angle in between them and we can solve this because that sin Θ by splitting both sides by qvB. So sin Θ is force separated by fee times speed times magnetic ar strength and then we take the station sin that both sides to number out the edge Θ. Therefore Θ is the inverse sin the F end qvB and also so we plug in numbers: station sin of 1.40 time 10 come the minus 16 newtons split by the charge times the rate times the magnetic ar strength and we gain 10.1 degrees but that"s no the end of the story because this is the picture for which this is the solution; we have the velocity rather to the right when the magnetic ar is to the right and this would certainly be an angle in between them of 10.1 degrees but the same magnitude pressure would happen if the velocity were virtually anti-parallel to the magnetic ar such that this, friend know, recommendation angle i m sorry is what her calculator tells you the smallest angle that provides the systems this referral angle is 10.1 or 10.0787 degrees but the angle Θ is gonna begin from this magnetic field and also go all the method to the velocity vector. Therefore this is a 180 degrees minus this 10.0787 degrees and this functions out come 170 degrees.
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