The solid acid reacts through the weak basic in the buffer to type a weak acid, i beg your pardon produces few H + ion in solution and therefore only a tiny change in pH.
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The solid acid reacts v the weak acid in the buffer to type a weak base, i m sorry produces couple of H+ ion in solution and therefore just a small change in pH.
The strong acid reacts v the solid base in the buffer to form a salt which, produces couple of H + ions in solution and also therefore only a small change in pH.
Consider a buffer equipment that covers a weak acid HA and also its conjugate base mathrmA^-.
When a solid acid is added to buffer solution then the conjugate base, mathrmA^- existing in buffer solution takes that is hydronium ion converting it into weak acid of conjugate base and also water.
mathrmH_3 mathrmO^+(a q)+mathrmA^-(a q) ightarrow mathrmH_2 mathrmO(l)+mathrmHA(a q)
Due come this, lot of weak mountain increases and amount that conjugate base decreases.
When a solid acid is added to the buffer systems then that reacts through weak basic in the buffer to kind a weak acid.
By adding strong acid in buffer solution, lot of weak mountain increases. So, there will be a tiny change in mathrmpH. Therefore, the correct alternative is as follows:
1. The strong acid reacts through the weak basic in the buffer to type a weak acid, i beg your pardon produces couple of mathrmH^+ ions in solution and also therefore just a small change in mathrmpH.
Amount that weak acid is raised by adding solid acid in the buffer solution. Since the acid formed is weak, that produces only a couple of mathrmH^+ ion in the buffer solution and mathrmpH the the buffer to reduce by a very little amount.
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