This means that the facets with the shortest ionization energies would certainly be in the bottom left-hand corner of the periodic table. The readjust in ionization energies is also bigger going down the periodic table (by adjust within a group) than going throughout the regular table (by change within a period).

You are watching: Rank the following elements according to their ionization energy.

So let"s start from the bottom of the regular table:#Pb# is the aspect that is in the lowest duration at 6 (and lowest team at 14) in the regular table; it"s the the smallest ionization energy.

The period above (5) has two the the elements: Sn and Te. Well, due to the fact that ionization energy increases throughout a period, Sn will have actually a smaller sized ionization energy than Te.#Pb, Sn, Te#

Now, let"s walk to the third period, where #S# and #Cl# are. Because #S# is prior to #Cl,# #S# has actually a lower ionization energy than #Cl#.#Pb, Sn, Te, S, Cl#

Ernest Z.
Nov 15, 2016

The stimulate is #"Sn .

Explanation:

You have actually learned the ionization energy increases from height to bottom and from left to best in the regular Table.

You most likely saw a diagram something choose this.

Here"s the portion of the routine Table that consists of the elements in this question.

You would normally predict the order to be

#"Pb

This is almost correct, but the exactly order is #"Sn , as displayed in the photo below.

Why is this so?

The electron construction of #"Sn"# is #" 5s"^2 "4d"^10 "5p"^2#.

The electron construction of #"Pb"# is #" 6s"^2 "4f"^14 "5d"^10 "6p"^2#.

The #"4f"# electrons in #"Pb"# are poor at shielding the outermost electrons.

Thus the external electrons endure a greater effective nuclear charge, and also it is more daunting to eliminate them.

Hence #"Pb"# has a greater ionization than #"Sn"#, and the exactly order is #"Sn .

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