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You are watching: The sum of two consecutive integers

To solve assign a variable the represents the an initial integer. Allow it be x.

Since the two integers space consecutive, to acquire the next integer, add 1 to the first number.So the second integer is x + 1.

Then, add the two integers x and also x+1. And, set it...

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To fix assign a variable the represents the first integer. Let it it is in x.

Since the two integers room consecutive, to gain the next integer, include 1 to the first number.So the second integer is x + 1.

Then, include the two integers x and x+1. And, set it same to the offered sum i m sorry is 8.

`x + x + 1 = 8`

Then, usage this equation to fix for x. So, integrate like terms.

`2x+1=8`

`2x+1-1=8-1`

`2x=7`

`x=7/2`

`x=3.5`

Notice the the resulting value of x has actually a decimal point, not an integer.

Hence, there space no continuous integers that has a amount equal come 8.

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