**Factors of 24** are basically the number that division it evenly or precisely without leaving any kind of remainder i.e if a number divides 24 through a remainder of zero, then the number is called a factor.

**All Factors:**1, 2, 3, 4, 6, 8, 12 and 24.

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**Prime factors:**2, 3.

**Factors in pairs:**(1,24), (2,12), (3,8), (4,6),(6,4),(8,3),(12,2).

**Prime administer of** 24

**Prime factorization** is a an approach of “**expressing**” or **finding **the provided number as the product of element numbers. If a number occurs much more than once in element factorization, it is generally expressed in exponential type to make it an ext compact.

The **prime factorization **comes the end to be**:** **2 × 2 × 2 × 3 = 23× 3**.

### Prime administrate of 24 by Upside-Down department Method

**Upside-Down department **is among the techniques used to perform the prime factorization of different numbers.

In this method, you will divide a provided “composite” number same by the several prime numbers(starting native the smallest) it rotates it gets a prime number.

It is called **Upside-Down Division** because the prize is flipped upside down.

Here, 24is an also number. So it is without doubt divisible through 2 through no remainder.Thus, 2 is its smallest prime factor.

And we gain 24÷ 2 = 12. Now find the prime components of the acquired quotient.

Repeat step 1 and Step 2 until we get a an outcome of element number together the quotient. Here, 12is the quotient.

12÷ 2 = 6. Here, 6 is the quotient.Now uncover the prime components of the 6.

6÷ 2= 3. Here, 3 is the prime number.

So we deserve to stop theprocess.

So, **prime factorization through upside-down department method** comes out to be:2× 2× 2× 3 = (2^3 imes 3).

**Prime administer of24 by factor Tree Method**

The** variable tree method** is another technique for producing the element factorization and also all determinants of a given number.

**To use this an approach for a number x**,

Firstly think about two determinants say **a,b** that x such that a*b is same to x and also at the very least one of them (a, b) is a prime aspect say a.

Then consider two factors of b say c, d such that again at least one of them is a prime factor. This process is repetitive until both the factors are prime i.e if we get both the determinants as element at any kind of step, we stop the procedure there.

Following is the variable tree that the given number.

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Here we can gain the prime factorisation the 24 together 2 * 2 * 2 * 3 and also the 2 prime factors are 2, 3

## FAQs

**What is the sum of the determinants of 24?**

Sum the all determinants of the compelled number = (23 + 1 – 1)/(2 – 1) × (31 + 1 – 1)/(3 – 1) = 60

**What room the usual Factors that 24 and 21?**

Since, the determinants of 24 space 1, 2, 3, 4, 6, 8, 12, 24 and the determinants of 21 are 1, 3, 7, 21.Hence, <1, 3> are the common factors that 24 and also 21.