so usually youd need to plug in every the x"s and also solve the quadradic equation because that each of lock so prefer for 1. Lets plug it in (6)2-7(-1)+6=0 so id very first remove parenthesis and simplify 6*2 and also 7*-1 to get 12+7+6=0 then come out through 25=0 which means no solution. Is that how im claimed to be doing this? i think its not my mathmatical abilities that is stumping me end its the im not sure what the inquiry wants native me so ns dont really require you to fix it if you watch my thought procedure and call me its right, thank you for acquisition your time to answer! :D

monitor • 1
add comment

2 answers By skilled Tutors

best Newest oldest
By: BestNewestOldest

4.6 (63)

Experienced Prof

about this tutor›
about this tutor›
Which of the following equations would have actually the roots x=6, x=−1? (options in description as well as my thoughts on it)x2-7x+6=0x2-7x-6=0x2+7x-6=0x2-5x+6=0

You are right that a source of an equation renders it true. Thus, if an equation has two roots, castle both make the equation true.

You are watching: Which equation has x = –6 as the solution?

These equations have zero ~ above the appropriate side. The makes factoring easy.

The equation (x-6)(x+1) = 0 has actually roots x=6 and x=-1. Expanding that (use F-O-I-L) gives:

x2 + x - 6x - 6 = 0

x2 - 5x - 6 = 0

There space other, also quicker, approaches for simple quadratic equations. Part of the goals of this difficulty is to obtain practice in choosing a method.

rise • 0 Downvote
add comment

4.9 (890)

Retired mathematics prof. Proficient Math Regents tutor.

around this tutor›
about this tutor›

A root of a polynomial role is a worth of x that provides the value of the role equal come zero.

By the factor Theorem, if c is a root climate x - c is a factor.

So, due to the fact that 6 and also -1 are both roots, x-6 and x-(-1) = x+1 space both factors.

(x - 6)(x + 1) = x2 - 5x - 6 = 0 (Is over there a typo in choice 4??)

upvoted • 0 Downvote
comments • 2

Carsyn F.

no sir

mark M.

then none of the four choices is correct.

Still looking for help? get the best answer, fast.

questioning a concern for cost-free

gain a free answer to a fast problem. Most questions answered in ~ 4 hours.

discover an online Tutor now

choose an expert and also meet online. No packages or subscriptions, pay only for the time you need.

¢ € £ ¥ ‰ µ · • § ¶ ß ‹ › « » > ≤ ≥ – — ¯ ‾ ¤ ¦ ¨ ¡ ¿ ˆ ˜ ° − ± ÷ ⁄ × ƒ ∫ ∑ ∞ √ ∼ ≅ ≈ ≠ ≡ ∈ ∉ ∋ ∏ ∧ ∨ ¬ ∩ ∪ ∂ ∀ ∃ ∅ ∇ ∗ ∝ ∠ ´ ¸ ª º † ‡ À Á Â Ã Ä Å Æ Ç È É Ê Ë Ì Í Î Ï Ð Ñ Ò Ó Ô Õ Ö Ø Œ Š Ù Ú Û Ü Ý Ÿ Þ à á â ã ä å æ ç è é ê ë ì í î ï ð ñ ò ó ô õ ö ø œ š ù ú û ü ý þ ÿ Α Β Γ Δ Ε Ζ Η Θ Ι Κ Λ Μ Ν Ξ Ο Π Ρ Σ Τ Υ Φ Χ Ψ Ω α β γ δ ε ζ η θ ι κ λ μ ν ξ ο π ρ ς σ τ υ φ χ ψ ω ℵ ϖ ℜ ϒ ℘ ℑ ← ↑ → ↓ ↔ ↵ ⇐ ⇑ ⇒ ⇓ ⇔ ∴ ⊂ ⊃ ⊄ ⊆ ⊇ ⊕ ⊗ ⊥ ⋅ ⌈ ⌉ ⌊ ⌋ 〈 〉 ◊


Calculus Geometry Precalculus Trigonometry Statistics Probability Elementary mathematics Word trouble Equations functions ... Word troubles Algebra aid College Algebra Math aid Math inquiry Math Equations Algebra Word problem Math Word problem Math difficulty Math aid For college


what room all the typical multiples of 12 and also 15

answers · 7

have to know just how to carry out this problem

answers · 8

what are approaches used to measure ingredients and also their devices of measure up

answer · 8

exactly how do you main point money

answers · 6

spimlify 4x-(2-3x)-5

answers · 12



Fiona B.

5 (5)

Jim L.

4.9 (1,858)

Cindy G.

5.0 (226)
See much more tutors

discover an virtual tutor

Download our complimentary app

A connect to the app was sent to your phone.

See more: Which Was The First Cell Viewed By The Light Microscope ? Cell Theory Quiz Home Ga

Please provide a precious phone number.
Google pat app Store
gain to know us
discover with united state
work-related with united state
Download our complimentary app
Google play application Store
Let’s store in touch
Tabs over spaces!

Need more convincing?

ideal in business due to the fact that 2005

Tutors by topic
Tutors by location
Sitemap terms of Use Privacy policy
© 2005 - 2021 chrischona2015.org, Inc. - all Rights reserved